Question

the length of rectangular field is 2 metre more than its breadth if the perimeter is 32 M find the area

Answer 1

I HOPE YOU HAVE GOT YOUR ANSWER ......

Answer 2

$\textbf{\underline{\underline{Answer :-}}}$

$\text{The area of the Rectangle is 63 sq.m}$

$\textbf{\underline{\underline{Explanation :-}}}$

Given :

Perimeter of the Rectangle = 32 m

Length is = 2 metre more than its breadth.

To find :

The area of the Rectangle

Solution :

Consider the Breadth as x

Consider the Length as 2 + x

To get the area we need to find the measures of length and Breadth of the Rectangle.

$\star$ Perimeter of Rectangle :

$\sf{\implies}$2(Length+Breadth)

$\sf{\implies}$2( 2+ x + x) = 32

$\sf{\implies}$ 4 + 2x + 2x = 32

$\sf{\implies}$ 4 + 4x = 32

$\sf{\implies}$ 4x = 32 - 4

$\sf{\implies}$ 4x = 28

$\sf{\implies}$ x = 28 ÷ 4

$\sf{\implies}$ x = 7

${\boxed{\bigstar{\sf\:{x = 7}}}}$

Value of x + 2

$\sf{\implies}$ x + 2

$\sf{\implies}$ 7 + 2

$\sf{\implies}$ 9

${\boxed{\bigstar{\sf\:{Length = 9\: m}}}}$

${\boxed{\bigstar{\sf\:{Breadth = 7 \: m}}}}$

As we got the measures we can now find the Area.

$\star$ Area of the Rectangle =

$\sf{\implies}$ Length × Breadth

$\sf{\implies}$ 7 × 9

$\sf{\implies}$ 63 sq.m

$\therefore$$\text{The area of the Rectangle is 63 sq.m}$