the length of rectangular field is increased by 50%and breadth is decreased by 50% to form a new rectangular field. find the percentage change in the area of the field. ( Ls mensuration plane figures)
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Let the initial Length be y meters and breadth be z meters.
Initial Area = yz meter^2
Final length = (150/100) x y .
=
Final Breadth = (50/100) x z.
=
Final area = 3yz/4
Percentage decrease = [tex] \frac{ yz - (\frac{3yz}{4}) }{yz} [/tex] x 100 = 25%
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Initial Area = yz meter^2
Final length = (150/100) x y .
=
Final Breadth = (50/100) x z.
=
Final area = 3yz/4
Percentage decrease = [tex] \frac{ yz - (\frac{3yz}{4}) }{yz} [/tex] x 100 = 25%
Hope it helps.
Please Mark As Brainliest if it helps
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