The length of rectangular field is twice it’s breath if the perimeter of the field is 228m find the dimensions of the field
mahishah2425:
Let's take breath x
Answers
Answered by
13
Let the width be a
Length = 2a
Perimeter = 228 m
=> 2 (L +B) = 228
=> a+2a = 114
=> 3a = 114
=> a = 38
Width = 38 m
Length = 76 m
Length = 2a
Perimeter = 228 m
=> 2 (L +B) = 228
=> a+2a = 114
=> 3a = 114
=> a = 38
Width = 38 m
Length = 76 m
Answered by
9
hii!!
here's ur answer...
given that the length of the rectangular field is twice of breadth.
let the breadth be x, therefore length will be 2x
perimeter of the rectangular field=228m
→ 2(l+b)=228m
→ 2(2x+x)=228m
→ 2×3x=228m
→ 3x=228/2
→ 3x=114m
→ x=114/3
→ x=38
hence breadth of the rectangular field=x
=38m
length of the rectangular field=2x
=2×38
=76m
★ verification ★
perimeter of rectangular field=2(l+b)
=2(76+38)
=2×114
=228m
hence verified...
hope this helps..!
<<<<<☺☺☺>>>>>
here's ur answer...
given that the length of the rectangular field is twice of breadth.
let the breadth be x, therefore length will be 2x
perimeter of the rectangular field=228m
→ 2(l+b)=228m
→ 2(2x+x)=228m
→ 2×3x=228m
→ 3x=228/2
→ 3x=114m
→ x=114/3
→ x=38
hence breadth of the rectangular field=x
=38m
length of the rectangular field=2x
=2×38
=76m
★ verification ★
perimeter of rectangular field=2(l+b)
=2(76+38)
=2×114
=228m
hence verified...
hope this helps..!
<<<<<☺☺☺>>>>>
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