the length of rod is l, charge density is lambda c/m find the electrostatic force exerted by ring on rod
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0
Answer:
V
Explanation:
Electric field due to rod 1 at a distance
′
d
′
is given by -
due to electric field from rod 1 rod 2 experiences an electric force.
So, force per unit length is given by (f)
f=
L
F
=Eλ (λ : charge/ length)
From (1),
f=
d
2kλ
2
.
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