Question

The length of rome history and a half times its breadth if the perimeter of floor of the room is 90 m find the length and the breadth room

Answer 1

Correct Question :

The length of room is three and a half times its breadth if the perimeter of floor of the room is 90 m find the length and the breadth room

Solution :

Given :

• The length of rome history and a half times its breadth.
• The perimeter of floor of the room is 90 m.

To find :

• The length and the breadth room =?

Step-by-step explanation :

Let, the breadth of the room be, x.

Then, the length of the room be, 3x/2.

It is Given that,

The perimeter of floor of the room is 90 m.

As We know that,.

Perimeter of the rectangle = 2(length + breadth)

Substituting the values in the above formula, we get,

90 = 2(x + 3x/2)

90 = 2 × (2x+3x)/2

90 = 2 × 5x/2

90 = 10x/2

10x = 90 × 2

x = (90 × 2)/10

x = 18.

Therefore, We got the value of, x = 18.

Hence,

.

The breadth of the room, x = 18 m

Then, the length of the room, 3x/2 = 54/2 = 27 m

Answer 2

${ \huge{ \bold{ \underline{ \underline{ \orange{Question:-}}}}}}$

The length of rome history and a half times its breadth if the perimeter of floor of the room is 90 m find the length and the breadth room ..

_______________

${ \huge{ \bold{ \underline{ \underline{ \red{Answer:-}}}}}}$

✒Given : -

• Perimeter of floor of the room is 90 m ..
• The length of rome history and a half times its breadth ..

✒To Find : -

• Length and Breadth of the room = ?

✒Let ,

• Breadth of the Room = y
• Then , the length of the Room will be = 3y/2

✒Formula Used : -

$\leadsto\sf{{ \small{ \bold{ \bold{ \bold{ \green{Perimeter\:of\:Rectangle=2(l+b)}}}}}}}$

✒On Substituting Values : -

$\dashrightarrow\sf{90=2\bigg(y=\dfrac{3y}{2}\bigg)}$

$\dashrightarrow\sf{90=2\times{\dfrac{(2y+3y}{2}}}$

$\dashrightarrow\sf{90=2\times{\dfrac{5y}{2}}}$

$\dashrightarrow\sf{90=\dfrac{10y}{2}}$

$\dashrightarrow\sf{10y=90\times{2}}$

$\dashrightarrow\sf{y=\cancel\dfrac{(90\times{2)}}{10}}$

$\leadsto\sf{{ \large{ \boxed{ \bold{ \bold{ \blue{y=18m}}}}}}}$

✒Therefore , the Value of y is 18m ..

✒So ,

$\dashrightarrow\sf{Breadth\:of\:the\:Room(y)=18m}$

$\dashrightarrow\sf{Length\:of\:the\:Rectangle=\dfrac{3(18)}{2}}$

$\dashrightarrow\sf{\cancel\dfrac{54}{2}}$

$\leadsto\sf\bold{27m.}$