Math, asked by XxOollMrVENOMIloOxX, 19 days ago

The length of room is 2 times its breadth and 5 times its height if the volume of room is 800m3 .find the cost of plastering its 4 walls at rs 12 per m2​

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Answers

Answered by Manthan251
0

Step-by-step explanation:

Let length breadth and height be L,B and H resp.

so, L=2B=5H

B=L/2, H= L/5

Vol= L*B*H= L*L/2*L/5 = L^3/10=800

L^3= 8000, L= 20m

Hence, B=10m, H= 4m

area of walls will be 2(L*H + B*H)

= 2(80+40)

=240 m2

Cost of plastering will be 12*240

= 2880 rupees

Answered by Malluponnu
0

Answer:

Let length breadth and height be L, B and H resp. so, L = 2B = 5H B = L / 2, H = L / 5 Vol = L'B'H = L'L / 2 "L / 5 = LA3 / 10 = 800 L ^ 3 = 8000, L = 20m Hence, B = 10m. H = 4m area of walls will be 2 (L'H + B * H) = 2 (80 + 40) = 240 m2 Cost of plastering will be 12 * 240 = 2880 rupees.

Step-by-step explanation:

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