Question

The length of seconds hand of watch is 1.5cm and its mass is7×10^-3 geam.its averagevangular momentum is

Answer 1

Answer:

P (angular momentum) = I w  where I = moment of inertia and w = angular freq.

I = 1/3 M L^2   for thin rod about one end

w = 2 pi f = 2 pi / T     where f is the frequency and T the period (60 sec)

P = 1/3 * 7 * 10^-6 kg  * (.015 m)^2 * 2 * pi / (60 sec)

P = 5.5 * 10E-11 kg m^2 /sec