the length of seconds pendulum at a place of gravity and gravitational acceleration G is a 9.8 M per second square
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Pendulum period in seconds
T ≈ 2π√(L/G)
L is length of pendulum in meters
G is gravitational acceleration = 9.8 m/s²
Period is inversely proportional to the square root of gravity.
So gravity goes down by 9.83/9.8 = 1.00306
Square root of that is 1.00153
so period is 1/1.00153 = 0.99847 seconds
T ≈ 2π√(L/G)
L is length of pendulum in meters
G is gravitational acceleration = 9.8 m/s²
Period is inversely proportional to the square root of gravity.
So gravity goes down by 9.83/9.8 = 1.00306
Square root of that is 1.00153
so period is 1/1.00153 = 0.99847 seconds
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