Question

the length of shadow of a 3 metre high pole at a certain time of the day is 3.6 m . What is the height of another pole whose shadow at that time is 54 m long​

Answer 1

(correction in the image - it's 54m and not 58m)

Let the sun's elevation at that certain point of time on that day be x

In the right triangle formed by the pole of 3m height

$tanx = \frac{3}{3.6} = \frac{1}{1.2} = \frac{10}{12} = \frac{5}{6} \: \: \: \: \: \: \: \: \: \: \: ...(i)$

now, let the height of the pole whose shadow is 54m long, be h

so, in the right triangle formed by the pole of 'h' m height

$tanx = \frac{h}{54} \\ from \: (i) \: tanx = \frac{5}{6} \\ so \\ \frac{5}{6} = \frac{h}{54} \\ h = \frac{5}{6} \times 54 \\ h = 5 \times 9 \\ h = 45 \: m$

Hence, height of the other pole is 45 m.

Answer 2

Step-by-step explanation:

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