Question

the length of shadow of a 7 meters high Pole is 3 meters at 9 o'clock in the morning then what is the angle of elevation of the Sun rays with the ground at the time ???​

Answer 1

Answer:

The answer is 60°

Step by step explaination:

Height of the pole ( AB ) = 15 m

length the of the shadow ( BC ) = 5√3 m

Angle of elevation = x°

In triangle ABC ,

<B = 90°

tan <x = AB/BC

= 15/( 5√3 )

= 3/√3

= ( √3 × √3 )/( √3 )

= √3

tan x = tan 60°

Therefore ,

x = 60°

I hope this may help u....❤️❤️❤️