Question

The length of Shadow of a tower of standing on the ground is found to be 60 M more when the sun angle of elevation changes from 30° 60° find the height of the tower

Answer 1

Answer :--Here, AB is the tower And DB is the shadow of 60m. And <ADB=30°changes to <ABC=60°.

We have to find AB height of tower.

In ΔADB

tan60=AB/DB

1/√3 =AB/60

60√3=AB

AB=34.641m