the length of side of a rhombus is a multiple of 5. If the perimeter of rhombs is 200 cm. Find the length of the side of rhombus.
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Let ABCD is a rhombus and AC and BD are its diagonals
=4× sides
Side of rhombus:
=
(
2
AC
)
2
+(
2
BD
)
2
=
(
2
24
)
2
+(
2
32
)
2
=
144+256
=
400
=20cm
Therefore perimeter =4×sides =4×20=80cm
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