Question

The length of side of a triangle iare 7cm,13cm and 12 cm. Find the length of altitude drawn on side 12cm from opposite vertex

Answer 1

a = 7cm , b = 13cm , c = 12cm

s = (a + b + c) / 2

= (7 + 13 + 12) / 2

= 32/2 = 16

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{16(16 - 7)(16 - 13)(16 - 12)}$

$\sqrt{16 \times 9 \times 3 \times 4}$

$24 \sqrt{3}$

$area \: of \: triangle \: = 24 \sqrt{3}$

$(1 \div 2 \: )\times b \times h =24 \sqrt{3}$

$(1 \div 2) \times 12 \times h = 24 \sqrt{3}$

$6h = 24 \sqrt{3}$

$h = 4 \sqrt{3} cm$


$thanks$