Question

The length of sides of a right angled triangle are in the ratio 3:4:5 and perimeter is 144cm find its sides and area

Answer 1

let the three sides of a triangle be
$3x + 4x + 5x \\ 3x + 4x + 5x = 144cm \\ 12x = 144 \\ x = \frac{144}{12} = 12 \\ so \: 1st \: side \: = 3x = 3 \times 12 = 36 \\ \: \: 2nd \: side \: = \: 4x = 4 \times 12 = 48 \\ 3rd \: side \: = 5x = 5 \times 12 = 60 \\ all \: the \: sides \: found$
for area, we are not sure about the base and height of the triangle.


mark as the brainliest !!!

Answer 2

hi mate,

answer :The area of triangle is 864 cm² and the height corresponding to the longest side is 28.8 cm.

Step-by-step explanation:

The length of the sides of a triangle are in the ratio 3:4:5. Let the length of sides be 3x,4x,5x.

It is given that the perimeter of the triangle is 144 cm.

Let

the side = 3 x 4 x 5 x

144 = 3x + 4 x + 5 x

x = 144 / 12

x = 12

now we multiply by

3* 12 = 36 Cm = a

4* 12=48cm = b

5* 12=60cm = c = base....

S = a+b+c/2

36 + 48 + 60/2

144/2 = 72

triangle area = √ s (s - a) (s-b) ( s-c)

triangle area

= √ 72 (72-36) (72-48) (72-60)

triangle area = √72 (36) (24) (12)

triangle area = √746496

triangle area=864cm²

triangle area = ½ * base * height

864 = ½* 60 *height

864 = 30 *height

height = 864/30 = 28.8 cm

The height corresponding to the longest side is 28.8 cm.

i hope it helps you....

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