the length of sides of equilateral triangle is 8 cm find it's altitude
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Answer:
4√3
Step-by-step explanation:
√3/4 * 8²=1/2*8*h
h=4√3
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Area of equilateral ∆ is √3/4 ×side× side . Let the∆ be ABC and height of it be AD
And here side is 8 cm.
Therefore , Area of ∆ ABC =√3 /4 × 8 × 8
=√3×2×8
=16 √3
Now ,
AREA of ∆ ABC = 1/2 × Base ×height
16 √3 = 1/2 × BC × AD
16√3 =1/2 ×8 ×AD
16√3 ×2÷8 =AD
4√3 = AD
Therefore height of equilateral∆ whose side is 8cm is 4√3 cm
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