Question

The length of tangent drawn to a circle of radius 5cm is 12 cm.Then the distance of external point to the centre of circle is​

Answer 1

this is answer of your question

Answer 2

Given:

length of tangent = 12 cm

radius of a circle = 5cm

To find:

distance of external point =?

Step-by-step explanation:

• Consider OP is the radius of a circle having a length of 5 cm.
• Let Q be the point outside the circle.
• The length of tangent PQ drawn to a circle is 12 cm.
• Now, we have to find the distance of an external point Q to the center of a circle O.

• From fig. OP ⊥ PQ

• By Pythagoras theorem,

        $OQ^2= OP^2 + PQ^2$

                 = $5^2 + 12^2$

                 = 25 + 144

                 = 169

           OQ = 13 cm

• Hence the distance of an external point to the center of a circle is​ 13  cm.

Refer to the following attachment: