Question

the length of tangent for an external point to a circle are equal .

Answer 1

To prove PT=QTPT=QT

Proof: Consider the triangle OPTOPT and OQTOQT.

OP=OQOP=OQ

∠OPT=∠OQT=90∘∠OPT=∠OQT=90∘

OT=OTOT=OT (common side)

Hence by RHS the triangles are equal.

Hence PT=QTPT=QT

Hence Proved.