Question

the length of the 2 diagonal of a rhombus are 16 cm and 14cm then the length of each side of the rhombus is ..​

Answer 1

Answer:

$a = \frac{ \sqrt{ {p}^{2} + {q}^{2} } }{2}$

a is side of rhombus

p and q are diagonals

$a = \frac{ \sqrt{ {16}^{2} + {14}^{2} } }{2}$

$a = \frac{ \sqrt{256 +196 } }{2}$

$a = \frac{ \sqrt{452} }{2}$

$a = \frac{2 \sqrt{113} }{2}$

$a = \sqrt{113}$

$a = 10.6$

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Answer 2

Given,

The length of one diagonal in cm$\[ = 16\]$

The length of other diagonal in cm$\[ = 14\]$

Solution,

Formula used, the length of a side of a rhombus$\[ = \frac{{\sqrt {d_1^2 + d_2^2} }}{2}\]$

Therefore, the length of the side of each rhombus is

$\[\begin{array}{l} = \frac{{\sqrt {{{\left( {16} \right)}^2} + {{\left( {14} \right)}^2}} }}{2}\\ = \frac{{\sqrt {256 + 196} }}{2}\\ = \frac{{\sqrt {452} }}{2}\\ = 10.63\end{array}\]$

Hence, the length of the side of each rhombus is $\[10.63\]$ cm.