Question

The length of the altitude of an equilateral triangle of side 2a units is *​

Answer 1

Answer:

$\sqrt{3a}$

Step-by-step explanation:

let the triangle be ABC with AD as it's altitude. Then D is the mid point of BC.

In right angled triangle ABD, we have

AB^2=AD^2+DB^2

==>AD^2=AB^2-DB^2

=4a^2-a^2

AD^2=3a^2

AD=

$\sqrt{3a}$