Math, asked by senmahadeb7, 28 days ago

The length of the arm of a square is 10 meters. If the length of each arm is increased by 3 m, what will be the change in the area of ​​the square?​

Answers

Answered by Anonymous
1

Answer:

Given, the length and breadth of a rectangle are in the ratio 3:2 respectively.

Given, the length and breadth of a rectangle are in the ratio 3:2 respectively.Then let the length and breadth of the rectangle be 3x,2x respectively.

Given, the length and breadth of a rectangle are in the ratio 3:2 respectively.Then let the length and breadth of the rectangle be 3x,2x respectively.If the sides of the rectangle are extended on each side by 1 m then length and breadth will be 3x+1 m and 2x+1 m.

Given, the length and breadth of a rectangle are in the ratio 3:2 respectively.Then let the length and breadth of the rectangle be 3x,2x respectively.If the sides of the rectangle are extended on each side by 1 m then length and breadth will be 3x+1 m and 2x+1 m.According to the problem,

Given, the length and breadth of a rectangle are in the ratio 3:2 respectively.Then let the length and breadth of the rectangle be 3x,2x respectively.If the sides of the rectangle are extended on each side by 1 m then length and breadth will be 3x+1 m and 2x+1 m.According to the problem,2

or, 20x+10=21x+7

or, 20x+10=21x+7or, x=3.

or, 20x+10=21x+7or, x=3.So length and breadth are 9,6 m respectively.

or, 20x+10=21x+7or, x=3.So length and breadth are 9,6 m respectively.Now area of the rectangle be 9×6=54 m

or, 20x+10=21x+7or, x=3.So length and breadth are 9,6 m respectively.Now area of the rectangle be 9×6=54 m 2

or, 20x+10=21x+7or, x=3.So length and breadth are 9,6 m respectively.Now area of the rectangle be 9×6=54 m 2 .

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