Question

The length of the base of a right angle triangle is 8cm and attitude is 7cm. find the length of hypotenuse corrected upto 2 decimal

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Answer 1

Given :

• Base of Right angles Triangle is 8 cm.

• Altitude/Height is 7 cm.

To Find :

• Length of Hypotenuse.

Solution :

$\longmapsto\tt{Base=8\:cm}$

$\longmapsto\tt{Altitude/Perpendicular=7\:cm}$

Using Pythagoras Theorem :

$\longmapsto\tt\bf{{(H)}^{2}={(B)}^{2}+{(P)}^{2}}$

$\longmapsto\tt{{(H)}^{2}={(8)}^{2}+{(7)}^{2}}$

$\longmapsto\tt{{(H)}^{2}=64+49}$

$\longmapsto\tt{{(H)}^{2}=113}$

$\longmapsto\tt{H=\sqrt{113}}$

$\longmapsto\tt\bf{H=10.63\:cm}$

So , The Length of Hypotenuse is 10.63 cm .

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Answer 2

Answer:

Given :

• Base of Right angles Triangle is 8 cm.

Altitude/Height is 7 cm.

To Find :

• Length of Hypotenuse.

Solution :

Base 8 cm

Altitude/Perpendicular =

Using Pythagoras Theorem:

→ (H)² = (B)² + (P)²

(H)² = 64 +49

→ (H)² = 113

→H=√113

→H=10.63 cm

So, The Length of Hypotenuse is 10.63 cm.

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Step-by-step explanation:

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