Math, asked by AhmadAbdullah1, 16 days ago

The length of the base of an isosceles triangle is 24 cm and the length of a leg is 20 cm. What is the ratio in which the center of the inscribed circle divides the altitude on the base?

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Answered by smrutij068
0

Answer:

The length of the base of isosceles triangle is 24 cm and the length of the leg is 20 cm. To Find :- Determine the ratio in which center of the inscribed circle divides the altitude on the base. ? Since, the altitude of an isosceles triangle bisects the base . → Altitude = 16 cm

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