Question

the length of the boundary of a triangle whose side are 210 CM 150 cm 340 CM respectively is equal to

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Answer 1

Appropriate Question:

• Find the length of the boundary of a triangle whose side are 210 cm 150 cm 340 cm respectively .

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Given : The sides of Triangle are 210 cm , 150 cm and 340 cm , respectively .

Need To Find : Boundary or [ Perimeter] of Triangle .

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❍ Finding Boundary of Triangle :

⠀⠀⠀⠀⠀Boundary of any shape is also know as Perimeter of that Shape .

⠀⠀⠀⠀⠀The Formula for Perimeter of Triangle is Given by :

$\underline {\frak{\dag As , \: We \:know \:that\::}}$

$\qquad \qquad \sf {\underline {\boxed {\star \pink{ Perimeter _{(Triangle)} = Side\:A + Side\:B + Side\:C\:units }}}}$

Where ,

• Side A , Side B & Side C are three sides of Triangle in cm .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \qquad :\implies \sf { Perimeter_{(Triangle)}= 210 + 150 + 340 }$

$\qquad \qquad :\implies \sf { Perimeter_{(Triangle)}= 360 + 340 }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Perimeter _{(Triangle)} = 700\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Perimeter \:of\:Triangle \:is\:700\: cm}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

• $\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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