Question

The length of the chord is 4cm. If its perpendicular distance from the center of the circle is 1.5 determine the radius of the circle

Answer 1

Let O be the Center.

Let BC be the chord of 4 cm

A is a point on chord BC so that OA is 1.5 cm

OA is also perpendicular to chord BC

Since, Perpendicular from the Center to the chord , bisect the chord ( a property of circle)

BA = 2 cm

Now, In triangle OAB by Pythagoras theorem

OB^2 = OA^2 + BA^2

OB^2 = 2^2 + 1.5^2

= 4 + 2.25

OB^2 = 6.25

OB = 2.5 com

So radius of the circle = 2.5 cm

Answer 2

Answer:

Let O be the Center.

Let BC be the chord of 4 cm

A is a point on chord BC so that OA is 1.5 cm

OA is also perpendicular to chord BC

Since, Perpendicular from the Center to the chord , bisect the chord ( a property of circle)

BA = 2 cm

Now, In triangle OAB by Pythagoras theorem

OB^2 = OA^2 + BA^2

OB^2 = 2^2 + 1.5^2

= 4 + 2.25

OB^2 = 6.25

OB = 2.5 com

So radius of the circle = 2.5 cm

Step-by-step explanation:

hope it works!!!!