Question

The length of the chord is at a distance of 12 cm from the centre of a circle of radius 13 cm is what

Answer 1

Answer:

5 cm

given distance of between chord and the centre is 2 centimetre and the radius of is 13 then to find the length of the chord that we considered as x , we we can use Pythagoras theorem to find the value of the

12 square plus x squared equals to radius square because of this we can find the value of x is equals to 5 cm

Answer 2

AB is chord of a circle with center O and OA is its radius OM ⊥ AB

Therefore, OA = 13 cm, OM = 12 cm

Now from right angled triangle OAM,

OA2 = OM2 + AM2 by using Pythagoras theorem,

132 = 122 + AM2

AM2 = 132 – 122

AM2 = 169 – 144

AM2 = 25

AM = 52

We know that OM perpendicular to AB

Therefore, M is the midpoint of AB

AB = 2 AM

AB = 2 (5)

AB = 10 cm

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