Question

The length of the chord of a circle is 30 cm and its distance from the centre is 8 cm. Then radius of the
circle is -



​

Answer 1

Step-by-step explanation:

Let AB be the chord of length 30 cm Given that distance from centre to the chord AB is OC = 8 cm OC⊥AB Þ AC = CB[Since perpendicular drawn from centre of the circle bisects the chord] ∴ AC = CB = 15 cm In right ΔOCA, OA2 = AC2 + OC2 = 152 + 82 = 225 + 64 = 289 ⇒ AC = 17 cm Thus the radius of the circle is 17 cm.