Question

the length of the common chord of two equal intersecting circles is 10 cm and the distance between the two centres is 6 cm find the radius of each circle

Answer 1

Answer:

$r_{1}$=$r_{2}$=2

Step-by-step explanation:

here the common chord is of length is 10 cm

the common chord is the sum of both the diagonal

as the diagonal is the biggest chord and distance between two radius is 6 cm

therefore,

   diagonal of one circle is =  10-6=4

  d=4

therefore r=d/2= 4/2 = 2 cm

therefore radius of both circles is 2 cm each

hope this answer helps

Answer 2

Answer:

Step-by-step explanation:

here the common chord is of length is 10 cm

the common chord is the sum of both the diagonal

as the diagonal is the biggest chord and distance between two radius is 6 cm

therefore,

   diagonal of one circle is =  10-6=4

  d=4

therefore r=d/2= 4/2 = 2 cm

therefore radius of both circles is 2 cm each

hope this answer helps