the length of the diagnals of square is 32cm find the perimeter of it
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diagonal=32cm
side=a cm
diagonal=√2a
32=√2a
a=16√2cm
perimeter=4a
p=64√2cm
side=a cm
diagonal=√2a
32=√2a
a=16√2cm
perimeter=4a
p=64√2cm
Jiyaa1:
so by putting the value of √2 we get 64×1.414=90.496
now it is coming, I didn't put the value of √2 that's y it was wrong
wr8
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Answered by
1
Using pythagoras theorem
32/2=16
Let side be x
x²=16²+16²
x²=256+256
x²=512
x=16 underoot 2
THEN PERIMETER
= 4*16 Underoot 2
=64 underoot 2
32/2=16
Let side be x
x²=16²+16²
x²=256+256
x²=512
x=16 underoot 2
THEN PERIMETER
= 4*16 Underoot 2
=64 underoot 2
wr8
wrong
why wriong
wrong
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