Question

the length of the diagnols of a square is 10√2cm. its area is​

Answer 1

Solution:-

Given:-

Diagonal of Square = 10√2 cm.

To Find:-

Perimeter of Square = ?

Area of Square = ?

Find:-

We know that, All the sides are equal in a Square and each angle is equal to 90°.

Let the sides of an Square be "x" cm.

∴ By Pythagoras Theorem,

=) ( 10√2)² = x² + x²

=) 100×2 = 2x²

=) x² = 100

=) x = √100

=) x = 10

Hence,

Sides of an Square = 10cm.

Now,

Perimeter of Square = 4 × Side

=) Perimeter = 4 × 10

=) Perimeter = 40cm

And

Area of Square = ( side)²

=) Area = 10²

=) Area = 100 cm²

Hence,

Perimeter of Square is 40cm.

Area of Square is 100cm².

Answer 2

Step-by-step explanation:

• we know , length of diagonal = √2side
• Therefore , 10√2 = √2side
• side = 10cm
• area = side×side
• = 10×10
• = 100cm^2
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