Question

The length of the diagonal of a cube is 12 root 3 find its lateral surface area

Answer 1

Diagonal of cube of side x is
 $x \sqrt{3} = \sqrt[3]{12}$
So x is 
 $x= ( \frac{ \sqrt[3]{12} }{ \sqrt{3} })$
So lateral surface area is
 $x^{2} = ( \frac{ \sqrt[3]{12} }{ \sqrt{3} })^2 = \frac{12^ \frac{2}{3} }{3}$