Math, asked by varshitajaiswal70, 5 days ago

The length of the diagonal of a quadrilateral is 50 cm and the perpendicular drawn to it from the opposite vertices are 10 cm. find the area of the quadrilateral.

Answers

Answered by jitendra999

Given:

Given:d=40cm

Given:d=40cmh

Given:d=40cmh 1

Given:d=40cmh 1 =12cm

Given:d=40cmh 1 =12cmh

Given:d=40cmh 1 =12cmh 2

Given:d=40cmh 1 =12cmh 2 =7.5cm

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral =

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 2

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )=

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )= 2

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )= 21

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )= 21 ×40(12+7.5)=20×19.5=390cm

Given:d=40cmh 1 =12cmh 2 =7.5cmArea of quadrilateral = 21 d(h 1 +h 2 )= 21 ×40(12+7.5)=20×19.5=390cm 2

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