The length of the diagonal of a rectangle is 10cm. If the length is 2cm longer than the width, find the length and the width of the rectangle.
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Answer:
the length and the width of the rectangle is 8 cm and 6 cm respectively.
Step-by-step explanation:
Given the diagonal length of the rectangle, we can use Pythagorean theorem to get the width and the length.
Now, let the width of the rectangle be x.
The length = x + 10
According to Pythagorean theorem:
10² = x² + (x + 2)²
100 = x² + x² + 4x + 4
100 = 2x² + 4x + 4
Divide through by 2:
50 = x² + 2x + 2
x² + 2x - 48 = 0
Let's solve for x as follows:
x² + 8x - 6x - 48 = 0
x(x + 8) - 6( x + 8) = 0
(x - 6)(x + 8) = 0
x = 6 or -8
We take the positive value. So, x = 6 cm
The width of the rectangle = 6 cm
The length = 6 + 2 = 8 cm
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