Question

The length of the diagonal of a rectangle whose sides are 8 cm and 6 cm is _______

Answer 1

Here is your answer

Length of diagonal =

$= \sqrt{8 {}^{2} + 6 {}^{2} } \\ = \sqrt{64 + 36} \\ = \sqrt{100} \\ = 10cm$
Hope it helps you

Answer 2

Let ABCD be the rectangle
Given, AB=8cm
BC=6cm
then,
CD=8cm
AD=6cm(because opposite sides of. rectangle are equal)
Then, ABC forms a right angled triangle....According to Pythagoras theorem,
(Hypotenuse)^2=(Side1)^2+(side2)^2
(diagonal)^2=6^2+8^2=36+64=100
diagonal=√100=10
therefore, diagonal=10cm