the length of the diagonal of a rhombus are 16 cm and 12 cm find the side of the Rhombus .
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Answer:
Step-by-step explanation:
Diagnol AC=16cm
Diagnol BD=12cm
we know that diagnols of a rhombus intersect and bisect each other.
Let O be the point of intersection of both the diagnols.
Therefore, AO=8cm And BO=6cm
We also know that diagnols of a rhombus intersect at right angles.
In a right angled triangle AOB, by Pythagoras theorem
AB^2=AO^2+BO^2
=>AB^2=8^2+6^2
=>AB^2=64+36
=>AB^2=100
=>AB=√100
=>AB=10
We know that all sides of a rhombus are equal. Therefore side of the Rhombus=10cm.
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0
Answer:
10 cm is your answer
Step-by-step explanation:
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