the length of the diagonal of a rhombus are 16 cm and 12 cm. the length of each side of the rhombus is _____ (a)8cm (b)9 cm (c)10 cm (d)12cm
Answers
Answer:
(c)10 cm
Step-by-step explanation:
Let ABC be the rhombus whose diagonals AC and D are length 16 cm and 12 cm respectively. Let A and B intersect at o Since the diagonals of a rhombus bisect each other at right angles,
therefore, AO =1/2AC=1/2×16 cm = 8 cm
and BO = 1/2 BD = 1/2 ×12 cm = 6 cm
Since triangle AOB is right triangle, right angled at O.
Therefore, by Pythagoras theorem AB = OA? + OB
= AB? -82 + 6= 64 + 36 = 100
> AB - 10 cm
Hence, the length of each side of the rhombus is 10 cm
JAI SHREE KRISHNA
Answer:
its 10cm
Step-by-step explanation:
diagonals of a rhombus divide each other perpencicularly. so you get 4 right angled triangles in the rhombus with two two sides 8cm (half of 16) and 6cm (half of 12).
the hypotenuse of the triangle is the side of the rhombus. so by Pythagoras theorem,
hypotenuse ^2 = 6^2 + 8^2
= 36 +64
= 100
= 10^2
hypotenuse or side = 10 cm