Question

THE LENGTH OF THE DIAGONAL OF A RHOMBUS ARE 24 AND 32 CM . THE LENGTH OF THE ALTITUDE OF THE RHOMBUS IS; A) 12 CM B) 12.8 C) 19 D) 19.2

Answer 1

Let ABCD be a rhombus with AC and BD as its diagonals.
We know that the diagonals of a rhombus bisect each other at right angles.
Let O be the intersecting point of both the diagonals.
Let AC=24cm and BD=32cm
OA=AC/2
OA= 24/2=12cm
OB=BD/2
OB=32/2=16cm
In rt.ΔAOB by Pythagoras theorem we have
AB²=OA²+OB²
=(12)²+(16)²
=144+256
=400
AB=20cm
Hence, each side of the rhombus is of length 20cm
Area of rhombus=1/2*AC*BD
=1/2*24*32
=12*32
Area of rhombus=base*altitude
12*32=20*h
19.2cm=h

Answer 2

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