Question

the length of the diagonal of a rhombus are 24cm and 18cm respectively find the length of each side of the Rhombus

Answer 1

Answer

The Rhombus given to us consists of two diagonals that intersect each other. We are also given with the measurement of each diagnol whose measurement are 24 and 18 cm.

We know that, the diagonal divides into two equal parts if there are two diagonals. So, there are four lines formed inside the Rhombus. Now, we willhu find the value of length of each side.

Measurement of the side AB :

$\sf \dashrightarrow {Perpendicular}^{2} + {Base}^{2} = {Hypotnous}^{2}$

$\sf \dashrightarrow {AO}^{2} + {BO}^{2} = {AB}^{2}$

$\sf \dashrightarrow {12}^{2} + {9}^{2} = {Hypotnous}^{2}$

$\sf \dashrightarrow 144 + 81 = {AB}^{2}$

$\sf \dashrightarrow 225 = {AB}^{2}$

$\sf \dashrightarrow \sqrt{{AB}^{2}} = \sqrt{225}$

$\sf \dashrightarrow AB = \sqrt{225}$

$\sf \dashrightarrow AB = 15 \: cm$

AB is one of it's side. So, all the sides measures same because, the Rhombus has all the sides as same measures.

Hence, the measurement of the side of Rhombus is 15 cm.