The length of the diagonal of a rhombus are 24cm and 32cm. then find the length of the side of the rhombus.
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Answer:
Let ABCD be a rhombus with AC and BD as its diagonals.
We know that the diagonals of a rhombus bisect each other at right angles.
Let O be the intersecting point of both the diagonals.
Let AC=24cm and BD=32cm
OA=AC/2
OA= 24/2=12cm
OB=BD/2
OB=32/2=16cm
In rt.ΔAOB by Pythagoras theorem we have
AB²=OA²+OB²
=(12)²+(16)²
=144+256
=400
AB=20cm
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