Question

The length of the diagonal of a square is 10√2 cm. Its area is *
1 point
50 sq cm
200 sq cm
1000 sq cm
100 sq cm​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Area\:of\:square=100\:cm^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Length \: of \: diagonal \: of \: square= 10 \sqrt{2} \: cm \\ \\ \red{\underline \bold{To \: Find :}}\\ \tt: \implies Area \: of \: square = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Diagonal \: of \: square = 10 \sqrt{2} \\ \\ \tt: \implies \sqrt{2} a = 10 \sqrt{2} \\ \\ \tt: \implies a = \frac{10 \sqrt{2} }{ \sqrt{2} } \\ \\ \green{\tt: \implies a = 10 \: cm} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: square = {a}^{2} \\ \\ \tt: \implies Area \: of \: square = {10}^{2} \\ \\ \green{\tt: \implies Area \: of \: square =100 \: cm^{2} }$

Answer 2

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$\tt{\huge{\purple{ ...................... }}}$

QUESTION :

The length of the diagonal of a square is 10√2 cm.

Its area is :

1. 50 sq cm

2. 200 sq cm

3. 1000 sq cm

4. 100 sq cm

SOLUTION :

Let the side of the required square be S.

So,

Diagonal = a√2

Now, the given value of the Diagonal is 10√2

So,

a√2 = 10√2

√2 is cancelled.

So, side of the square is 10 m.

Area of the square = a ^ 2 = 100 m..... [ 4 ]