Question

the length of the diagonal of a square is 10 cm find its perimeter​

Answer 1

Answer:

28.28

Step-by-step explanation:

Use the formulas

$D = \sqrt{2a} \\\\P = 4S\\\\S = side$

Answer 2

Answer:

Suppose the square is ABCD

Suppose the square is ABCDwhere AB =xcm and BC=10cm

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cm

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50=>x=5√2

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50=>x=5√2So the sides of square are of 5√2cm

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50=>x=5√2So the sides of square are of 5√2cmSo the perimeter will be 4×side

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50=>x=5√2So the sides of square are of 5√2cmSo the perimeter will be 4×side=4×5√2cm

Suppose the square is ABCDwhere AB =xcm and BC=10cmdiagonal of square is =10cmas we know that the sides of the square are equal So by applying Pythagoras theorem,AB^2+AC^2=BC^2therefore,x^2+x^2=10^2=>2x^2=100=>x^2=50=>x=5√2So the sides of square are of 5√2cmSo the perimeter will be 4×side=4×5√2cm=20√2cm ans