Question

the length of the diagonal of a square is 36cm find i) area of square ii) the perimeter upto 2 decimal places​

Answer 1

Step-by-step explanation:

let a be the side of square

by Pythagoras theorem

a^2 + a^2 = 36

2a^2 =36

a^2 =18

a = 4.24 cm

area of square = 18 cm^2

perimeter = (4*a) =(4*4.24)

= 16.97 cm

Answer 2

Step-by-step explanation:

let a be the side of square

by Pythagoras theorem

a^2 + a^2 = 36

2a^2 =36

a^2 =18

a = 4.24 cm

area of square = 18 cm^2

perimeter = (4*a) =(4*4.24)

= 16.97 cm