Question

The length of the diagonal of a square is 8/2 cm.
Find the length of its side and hence find the area
of the square​

Answer 1

Length of diagonal=8✓2

2a² 2=64×2

area =a 2 =64cm 2

a=8cm

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Answer 2

Given :

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Length of the diagonal of a square is $\sf \: 8\sqrt{2 } \sf \: cm$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

To Find :

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• Length of its side
• Area of the square

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Solution :

As we know that,

• Diagonal of square is $\sf \: \sqrt{(2)} \times side$

Now solving,

➛ 8 √(2)cm = √(2) × side

➛ Side = 8 √(2)cm /√(2)

➛ Side = 8 cm

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

So, now we need to find out the area of the square,

As we know that,

• Area of the square = side × side

➛ 8 cm × 8 cm

➛ 64cm²

∴ Hence, the length of its side is 8cm and area of the square is 64cm² respectively.