the length of the diagonal of a square is 8cm. find its area
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Answer:
Here, ABCD is a square.
Let AB=BC=CD=AD=a [ All sides of square are equal ]
⇒ AC=8cm [ Given ]
In right angled △ABC,
⇒ (AC)
2
=(AB)
2
+(BC)
2
[ By Pythagoras theorem ]
⇒ (8)
2
=a
2
+a
2
⇒ 64=2a
2
⇒ a
2
=32
⇒ Area of a square =a
2
=32cm
2
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