Question

the length of the diagonal of rhombus 16cm and 12cm respectively. find the length of each of its sides

Answer 1

Since diagonals bisect each other at 90°.

So side^2 = (d1/2)^2 + (d2/2)^2

Side ^2 = (16/2)^2 + (12/2)^2

Side^2 = 8^2 + 6^2

Side^2 = 64 + 36

Side^2 = 100

Side = 10 cm.

Hope it's helpful to u.

Answer 2

Let us suppose that there is a rhombus ABCD IN which AC=16cm and BD=12cm and they are intersecting at O

Now,
we know that O will bisect the diagonals at 90°

by using pythogoras theorem

we found the the side measures 12cm

therefore sides of the rhombus is 10cm