Question

the length of the diagonal of rhombus 16cm and 12cm respectively. find the length of each of its sides

Answer 1

As we know diagonals of rhombus bisect each other at 90°
So 1/2of d1 = 8
And 1/2of d2=6
So it will form a right angle triangle and side of rhombus is hypotenuse
So 8²+6²=side of rhombus²
100= s²
S=10
Length of side =10cm

Answer 2

Answer:

Step-by-step explanation:

Since diagonals bisect each other at 90°.

So side^2 = (d1/2)^2 + (d2/2)^2

Side ^2 = (16/2)^2 + (12/2)^2

Side^2 = 8^2 + 6^2

Side^2 = 64 + 36

Side^2 = 100

Side = 10 cm.