the length of the diagonal of rhombus 16cm and 12cm respectively. find the length of each of its sides
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Answered by
5
As we know diagonals of rhombus bisect each other at 90°
So 1/2of d1 = 8
And 1/2of d2=6
So it will form a right angle triangle and side of rhombus is hypotenuse
So 8²+6²=side of rhombus²
100= s²
S=10
Length of side =10cm
So 1/2of d1 = 8
And 1/2of d2=6
So it will form a right angle triangle and side of rhombus is hypotenuse
So 8²+6²=side of rhombus²
100= s²
S=10
Length of side =10cm
Answered by
2
Answer:
Step-by-step explanation:
Since diagonals bisect each other at 90°.
So side^2 = (d1/2)^2 + (d2/2)^2
Side ^2 = (16/2)^2 + (12/2)^2
Side^2 = 8^2 + 6^2
Side^2 = 64 + 36
Side^2 = 100
Side = 10 cm.
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