The length of the diagonal of square is 10√2 . It's area is
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The diagonal of square = √2side
10√2 = √2side
side = 10√2/√2
side = 10
Area = side^2
Area = 10*10
Area = 100 square unit
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Given :
• Length of the diagonal of square = 10√2
To Find :
• Area of the square.
Solution :
Let the side of the square be a. We know that all the sides are equal of square.
Applying Pythagoras Theorem :
★ (Hypotenuse)² = (Perpendicular)² + (Base)²
→ (10√2)² = (a)² + (a)²
→ 100 × 2 = a² + a²
→ 200 = 2a²
→ a² =
→ a² = 100
→ a = √100
→ a = 10 units
We've obtained the side of square, let's find area now.
★ Area of Square = (Side)²
→ (10)²
→ 10 × 10
→ 100 units.
Area of the square is 100 units.
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