The length of the diagonals of a rhombus are 16 cm and 12 cm respectively. The perimeter of the rhombus in cm is
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The length of the two diagonals of a rhombus = 16 cm and 12 cm respectively.
The rhombus have right angle formed between its diagonals.
Then a rt Δ will form there.
Then the two sides of the right triangle will be 8 cm and 6 cm respectively.
Using Pythagoras property,
⇒A²+ B² = C²
⇒6² + 8² = C² [ it's one side]
⇒36 + 64 = 100
⇒100 = 10²
Then each side of the rhombus is 10 cm.
Then the perimeter of the rhombus is
⇒10 x 4 = 40 cm.
Hope this answer can helps you dear...♥
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