the length of the diagonals of a rhombus are 16 cm and 12 cm for class 8 th
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The sides of Rhombus are 10 cm.
Step-by-step explanation:
As the question mentioned there are 2 diagonals
The length of the first diagonal is 12 cm, whereas the length of the second diagonal is 16 cm
We divide the rhombus into 4 parts, let us take part 1:
As the diagram shown below, using Pythagoras theorem we find s
Now as we know that BD = 16 cm and AC = 12 cm; therefore to find S
We use,
(\frac{B D}{2})^{2}+(\frac{A C}{2})^{2}=S^{2}(
2
BD
)
2
+(
2
AC
)
2
=S
2
Putting the values of BD and AC, we get,
(\frac{16}{2})^{2}+(\frac{12}{2})^{2}=S^{2}(
2
16
)
2
+(
2
12
)
2
=S
2
(8)^{2}+(6)^{2}=S^{2}(8)
2
+(6)
2
=S
2
\sqrt{100}=S
100
=S
\therefore S=10 \ \mathrm{cm}∴S=10 cm
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