Question

the length of the diagonals of a rhombus are 16 cm and 12 cm for class 8 th​

Answer 1

Answer:

what can be find in this question

Answer 2

The sides of Rhombus are 10 cm.

Step-by-step explanation:

As the question mentioned there are 2 diagonals

The length of the first diagonal is 12 cm, whereas the length of the second diagonal is 16 cm

We divide the rhombus into 4 parts, let us take part 1:

As the diagram shown below, using Pythagoras theorem we find s

Now as we know that BD = 16 cm and AC = 12 cm; therefore to find S

We use,

(\frac{B D}{2})^{2}+(\frac{A C}{2})^{2}=S^{2}(

2

BD

)

2

+(

2

AC

)

2

=S

2

Putting the values of BD and AC, we get,

(\frac{16}{2})^{2}+(\frac{12}{2})^{2}=S^{2}(

2

16

)

2

+(

2

12

)

2

=S

2

(8)^{2}+(6)^{2}=S^{2}(8)

2

+(6)

2

=S

2

\sqrt{100}=S

100

=S

\therefore S=10 \ \mathrm{cm}∴S=10 cm