The length of the diagonals of a rhombus are 16 cm and 12 CM calculate the perimeter of the Rhombus
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perimeter is 260 cm^2 i hope it help you
Shriyachoksi9:
But how?
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side of rhombus =
let its side be x
By pythagoras theorem ,
(1/2×16)^2 +(1/2×12)^2=x^2
64+36 = x^2
100=x^2
underroot 100 = x
10 = x
perimeter of rhombus = 4×side
= 4×10cm
=40cm
Have a nice day.
let its side be x
By pythagoras theorem ,
(1/2×16)^2 +(1/2×12)^2=x^2
64+36 = x^2
100=x^2
underroot 100 = x
10 = x
perimeter of rhombus = 4×side
= 4×10cm
=40cm
Have a nice day.
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