Question

the length of the diagonals of a rhombus are 20cm and 48 cm. find the perimeter of the rhombus. by full process

Answer 1

Hey mate!!

Solution:

Perimeter of a Rhombus = 2√(p²+q²)

Given, p=48 q=20

Perimeter of a Rhombus = 2√(48²+20²)

=2√(2304+400)

=2√(2704)

=2 × 52

=104 cm²

Answer 2

❤❤Here is your answer ✌ ✌

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$\huge\underline{\blue{\bold{Given}}}$
$<b>$
Length of the diagonals of a rhombus are 20cm and 48 cm

$perimeter \: of \: rhombus \\ = 2 \sqrt{p {}^{2} + q {}^{2} } \\ = 2 \sqrt{48 {}^{2} + 20 {}^{2} } \\ = 2 \sqrt{2304 + 400} \\ = 2 \sqrt{2704} \\ = 2 \times 52 \\ = 104cm$